49r^2-100=0

Solution for 49r^2-100=0 equation:

49r^2-100=0

a = 49; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·49·(-100)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*49}=\frac{-140}{98}
=-1+3/7
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*49}=\frac{140}{98}
=1+3/7
$